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-5x^2=-11x-5
We move all terms to the left:
-5x^2-(-11x-5)=0
We get rid of parentheses
-5x^2+11x+5=0
a = -5; b = 11; c = +5;
Δ = b2-4ac
Δ = 112-4·(-5)·5
Δ = 221
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{221}}{2*-5}=\frac{-11-\sqrt{221}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{221}}{2*-5}=\frac{-11+\sqrt{221}}{-10} $
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